(x-4)(2x^2-3x+5)=

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Solution for (x-4)(2x^2-3x+5)= equation:


Simplifying
(x + -4)(2x2 + -3x + 5) = 0

Reorder the terms:
(-4 + x)(2x2 + -3x + 5) = 0

Reorder the terms:
(-4 + x)(5 + -3x + 2x2) = 0

Multiply (-4 + x) * (5 + -3x + 2x2)
(-4(5 + -3x + 2x2) + x(5 + -3x + 2x2)) = 0
((5 * -4 + -3x * -4 + 2x2 * -4) + x(5 + -3x + 2x2)) = 0
((-20 + 12x + -8x2) + x(5 + -3x + 2x2)) = 0
(-20 + 12x + -8x2 + (5 * x + -3x * x + 2x2 * x)) = 0
(-20 + 12x + -8x2 + (5x + -3x2 + 2x3)) = 0

Reorder the terms:
(-20 + 12x + 5x + -8x2 + -3x2 + 2x3) = 0

Combine like terms: 12x + 5x = 17x
(-20 + 17x + -8x2 + -3x2 + 2x3) = 0

Combine like terms: -8x2 + -3x2 = -11x2
(-20 + 17x + -11x2 + 2x3) = 0

Solving
-20 + 17x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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